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Sharma hits 28th ODI ton as India wins series v Australia

BENGALURU, India (AP) — Rohit Sharma scored his 28th ODI hundred as India beat Australia by seven wickets with 15 balls remaining to win the three-match series 2-1 on Sunday.

Sharma scored 119 runs off 128 balls with eight fours and six sixes as he anchored India’s run-chase in the third and final one-day international. Virat Kohli contributed a superb 89 off 91 balls as the hosts scored 289-3 in 47.3 overs.

This was in reply to Australia’s 286-9. Steve Smith (131) reached his first hundred in three years, while Marnus Labuschagne (54) scored his first ODI half-century after the visitors won the toss and opted to bat.

India’s bowlers, led by Mohammed Shami’s 4-63, did well in restricting Australia to a sub-par total.

Sharma and Kohli then put on 137 runs for the second wicket to deny Australia any chance of a comeback as India clinched the series.

Australia had won the first ODI in Mumbai by 10 wickets. India won the second ODI in Rajkot by 36 runs.

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More AP sports: https://apnews.com/apf-sports and https://twitter.com/AP_Sports

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